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9216=16t^2
We move all terms to the left:
9216-(16t^2)=0
a = -16; b = 0; c = +9216;
Δ = b2-4ac
Δ = 02-4·(-16)·9216
Δ = 589824
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{589824}=768$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-768}{2*-16}=\frac{-768}{-32} =+24 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+768}{2*-16}=\frac{768}{-32} =-24 $
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